Capacitors in Parallel

• Voltage remains the same
• Equivalent Capacitance = C1 + C2 + C3 ….

• C = Q / V
• For A:
  • 3 = Q / 8
  • Q = 24
• For B:
  • 6 = Q / 8
  • Q = 48

• So C1 (24) + C2 (48) = 72C (equiv)
• C_eq = 6F + 3F = 9F
• Capacitor A has twice the Farad (F) –> therefore twice the charge

 

The above is the equivalent to:

• C = Q / V
• 9F = Q / 8V
• Q = 72C

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